A and B working together completed a job in 5 days. If A works twice as efficiently as he actually did and B works \(\frac{1}{3}\) of actual efficiency, the work would have been completed in 3 days. Find the for A to complete the job alone.
\(6\frac{1}{2}\)
\(6\frac{1}{4}\)
\(6\frac{3}{4}\)
\(12\frac{1}{2}\)
None of these
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A can do a piece of work in 6 days. B is 25% more efficient than A. How long would B alone take to finish this work ?
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A and B together can complete a task in 20 days. B and C together can complete the same task in 30 days. A and C together can complete the same task in 40 days. What is the respective ratio of the number of days taken by A when completing the same task alone to the number of days taken by C when completing the same task alone?
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