Quiz Discussion

Simplify : \(1 + {2 \over {1 + {3 \over {1 + {4 \over 5}}}}}\)

• 1]

  7/4

• 2]

  4/7

• 3]

  7/5

• 4]

  3/7

1 - [5 - {2 + (- 5 + 6 - 2) 2}] is equal to:

• 1] -4
• 2] 2
• 3] 0
• 4] 2

The value of \(\frac{{{{\left( {x - y} \right)}^3} + {{\left( {y - z} \right)}^3} + {{\left( {z - x} \right)}^3}}}{{{{\left( {{x^2} - {y^2}} \right)}^3} + {{\left( {{y^2} - {z^2}} \right)}^3} + {{\left( {{z^2} - {x^2}} \right)}^3}}}\)       is = ?

• 1]

  0

• 2]

  1

• 3]

  \({\left[ {2\left( {x + y + z} \right)} \right]^{ - 1}}\)

• 4]

  \({\left[ {\left( {x + y} \right)\left( {y + z} \right)\left( {z + x} \right)} \right]^{ - 1}}\)

If the expression \({ \text{2}}\frac{1}{2}{ \text{ of }}\frac{3}{4} \times \frac{1}{2} \div \frac{3}{2} + \frac{1}{2} \div \frac{3}{2}\left[ {\frac{2}{3} - \frac{1}{2}{ \text{ of }}\frac{2}{3}} \right]\) is simplified, we get -

• 1]

  1/2

• 2]

  7/8

• 3]

  \({ \text{1}}\frac{5}{8}\)

• 4]

  \({ \text{2}}\frac{3}{5}\)

\(1\frac{3}{4} - 1\frac{1}{5} + 1\frac{5}{8} = ?\)

• 1]

  \(2\frac{7}{{40}}\)

• 2]

  \(3\frac{7}{{40}}\)

• 3]

  \(9\frac{5}{8}\)

• 4]

  \(10\frac{7}{8}\)

• 5]

  None of these

1559.95 - 7.99 × 24.96 - ?2 = 1154

• 1] 14
• 2] 24
• 3] 32
• 4] 18
• 5] 8

Simplify : \(\left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) - \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right) \times \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] \div \left[ {\left( {1 + \frac{1}{{10 + \frac{1}{{10}}}}} \right) + \left( {1 - \frac{1}{{10 + \frac{1}{{10}}}}} \right)} \right] = ?\)

• 1]

  100/101

• 2]

  90/101

• 3]

  20/101

• 4]

  101/100

3.325 + 3.012 + 0.660 + 31.151 + 0.251 = ?

• 1]

  40.019

• 2]

  35.055

• 3]

  37.514

• 4]

  38.399

Let a = (4 ÷ 3) ÷ 3 ÷ 4, b = 4 ÷ (3 ÷ 3) ÷ 4, c = 4 ÷ 3 ÷ (3 ÷ 4), The maximum value among the above three is?

• 1] a
• 2] b
• 3] c
• 4] All equal

4848 / 24 * 11 - 222 = ?

• 1]

  200

• 2]

  2444

• 3]

  2000

• 4]

  \(115\frac{3}{8}\)