Quiz Discussion

0.002 x 0.5 = ?

• 1] 0.0001
• 2] 0.001
• 3] 0.01
• 4] 0.1

Which of the following are in descending order of their value ?

• 1]

  \(\frac{1}{3},\frac{2}{5},\frac{3}{7},\frac{4}{5},\frac{5}{6},\frac{6}{7}\)

• 2]

  \(\frac{1}{3},\frac{2}{5},\frac{3}{5},\frac{4}{7},\frac{5}{6},\frac{6}{7}\)

• 3]

  \(\frac{1}{3},\frac{2}{5},\frac{3}{5},\frac{4}{6},\frac{5}{7},\frac{6}{7}\)

• 4]

  \(\frac{6}{7},\frac{5}{6},\frac{4}{5},\frac{3}{7},\frac{2}{5},\frac{1}{3}\)

\(3.\overline {87} - 2.\overline {59} = ?\)

• 1]

  1.20

• 2]

  \(1.\overline 2 \)

• 3]

  \(1.\overline {27} \)

• 4]

  \(1.\overline {28} \)

47.7 × 12.4 × 8.6 = ?

• 1] 5086.728
• 2] 5218.668
• 3] 5708.428
• 4] 6180.656
• 5] None of these

The value of \(\frac{{{{\left( {0.96} \right)}^3} - {{\left( {0.1} \right)}^3}}}{{{{\left( {0.96} \right)}^2} + 0.096 + {{\left( {0.1} \right)}^2}}}{ \text{is}}:\)

• 1] 0.86
• 2] 0.95
• 3] 0.97
• 4] 1.06

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?

• 1]

  2010

• 2]

  2011

• 3]

  2012

• 4]

  2013

0.04 x 0.0162 is equal to:

• 1] 6.48 x 10-3
• 2] 6.48 x 10-4
• 3] 6.48 x 10-5
• 4] 6.48 x 10-6

Solve \(\frac{294 ÷ 14 × 5 + 11}{?}\)    = 82 ÷ 5 + 1.7

• 1] 8
• 2] 6
• 3] 12
• 4] 5
• 5] 10

\(\frac{{{{\left( {0.013} \right)}^3} + 0.000000343}}{{{{\left( {0.013} \right)}^2} - 0.000091 + 0.000049}} = \,?\) = ?

• 1] 0.002
• 2] 0.020
• 3] 0.021
• 4] 0.023

The place value of 9 in 0.06945 is :

• 1]

  9

• 2]

  9/10

• 3]

  9/100

• 4]

  9/1000