Quiz Discussion

If the sums of n terms of two arithmetic progressions are in the ratio \(\frac{{3n + 5}}{{5n + 7}}\)   then their nth terms are in the ration

 

Course Name: Quantitative Aptitude

  • 1]

    \(\frac{{3n - 1}}{{5n - 1}}\)

  • 2]

    \(\frac{{3n + 1}}{{5n + 1}}\)

  • 3]

    \(\frac{{5n + 1}}{{3n + 1}}\)

  • 4]

    \(\frac{{5n - 1}}{{3n - 1}}\)

Solution
No Solution Present Yet

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# Quiz
1
Discuss

Consider an infinite G.P. with first term a and common ratio r, its sum is 4 and the second term is 3/4, then

  • 1]

    a = 7/4, r = 3/7

  • 2]

    a = 2, r = 3/8

  • 3]

    a = 3, r = 1/4

  • 4]

    a = 3/2, r = ½

Solution
2
Discuss

What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 3?

  • 1]

    897

  • 2]

    1,64,850

  • 3]

    1,64,749

  • 4]

    1,49,700

Solution
3
Discuss

If the sum of n terms of an A.P. is 3n2 + 5n then which of its terms is 164 ?

  • 1] 26th
  • 2] 27th
  • 3] 28th
  • 4] None of these
Solution
4
Discuss

A square is drawn by joining the mid points of the sides of a given square in the same way and this process continues indefinitely. If a side of the first square is 4 cm, determine the sum of the areas all the square.

  • 1] 32 Cm2
  • 2] 16 Cm2
  • 3] 20 Cm2
  • 4] 64 Cm2
  • 5] None of these
Solution
5
Discuss

The 2nd and 8th term of an arithmetic progression are 17 and -1 respectively. What is the 14th term?

  • 1]

    -19

  • 2]

    -22

  • 3]

    -20

  • 4]

    -25

Solution
6
Discuss

What is the sum of the following series? -64, -66, -68, ......, -100

  • 1] -1458
  • 2] -1558
  • 3] -1568
  • 4] -1664
Solution
7
Discuss

If k, 2k – 1 and 2k + 1 are three consecutive terms of an AP, the value of k is

  • 1] -2
  • 2] 3
  • 3] -3
  • 4] 6
Solution
8
Discuss

If an A.P. has a = 1, tn = 20 and sn = 399, then value of n is :

  • 1] 20
  • 2] 32
  • 3] 38
  • 4] 40
Solution
9
Discuss

If a + 1, 2a + 1, 4a - 1 are in A.P., then the value of a is:

  • 1] 1
  • 2] 2
  • 3] 3
  • 4] 4
Solution
10
Discuss

A bacteria gives birth to two new bacteria in each second and the life span of each bacteria is 5 seconds. The process of the reproduction is continuous until the death of the bacteria. initially there is one newly born bacteria at time t = 0, the find the total number of live bacteria just after 10 seconds :

  • 1]

    \(\frac{{{3^{10}}}}{2}\)

  • 2]

    310 - 210

  • 3]

    243 × (35 -1)

  • 4]

    310 - 25

  • 5]

    None of these

Solution
# Quiz