Quiz Discussion

A boy agrees to work at the rate of one rupee on the first day, two rupees on the second day, and four rupees on third day and so on. How much will the boy get if he started working on the 1st of February and finishes on the 20th of February?

Course Name: Quantitative Aptitude

  • 1] 220
  • 2] 220 -1
  • 3] 219 -1
  • 4] 219
  • 5] None of these
Solution
No Solution Present Yet

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# Quiz
1
Discuss

What is the sum of all positive integers up to 1000, which are divisible by 5 and are not divisible by 2?

  • 1] 10,050
  • 2] 5050
  • 3] 5000
  • 4] 50,000
Solution
2
Discuss

What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 3?

  • 1]

    897

  • 2]

    1,64,850

  • 3]

    1,64,749

  • 4]

    1,49,700

Solution
3
Discuss

A bacteria gives birth to two new bacteria in each second and the life span of each bacteria is 5 seconds. The process of the reproduction is continuous until the death of the bacteria. initially there is one newly born bacteria at time t = 0, the find the total number of live bacteria just after 10 seconds :

  • 1]

    \(\frac{{{3^{10}}}}{2}\)

  • 2]

    310 - 210

  • 3]

    243 × (35 -1)

  • 4]

    310 - 25

  • 5]

    None of these

Solution
4
Discuss

If log 2, log (2x -1) and log (2x + 3) are in A.P, then x is equal to ___

  • 1]

     

    5/2

  • 2]

    log25

  • 3]

    log32

  • 4]

     

    3/2

Solution
5
Discuss

For A.P. T18 - T8 = ........ ?

  • 1] d
  • 2] 10d
  • 3] 26d
  • 4] 2d
Solution
6
Discuss

If the sum of the series 2 + 5 + 8 + 11 … is 60100, then the number of terms are

  • 1]

    100

  • 2]

    150

  • 3]

    200

  • 4]

    250

Solution
7
Discuss

If the 7th term of a H.P. is 1/10 and the 12th term is 1/25, then the 20th term is

  • 1]

    1/41

  • 2]

    1/45

  • 3]

    1/49

  • 4]

    1/37

Solution
8
Discuss

The number of terms of the A.P. 3, 7, 11, 15, ....... to be taken so that the sum is 406 is

  • 1]

    5

  • 2]

    10

  • 3]

    12

  • 4]

    14

Solution
9
Discuss

(1) + (1 + 1) + (1 + 1 + 1) + ....... + (1 + 1 + 1 + ...... n - 1 times) = ......

  • 1]

    \(\frac{{n\left( {n + 1} \right)}}{2}\)

  • 2]

    \(\frac{{n\left( {n - 1} \right)}}{2}\)

  • 3]

    \({n^2}\)

  • 4]

    n

Solution
10
Discuss

Which term of the A.P. 92, 88, 84, 80, ...... is 0?

  • 1] 23
  • 2] 32
  • 3] 22
  • 4] 24
Solution
# Quiz