Quiz Discussion

If \(\frac{{144}}{{0.144}} = \frac{{14.4}}{x}\)   then the value of x is:

• 1] 0.0144
• 2] 1.44
• 3] 14.4
• 4] 144

\(\frac{{{{\left( {0.013} \right)}^3} + 0.000000343}}{{{{\left( {0.013} \right)}^2} - 0.000091 + 0.000049}} = \,?\) = ?

• 1] 0.002
• 2] 0.020
• 3] 0.021
• 4] 0.023

The fraction \( 101\frac{{27}}{{100000}}\)   in decimal for is

• 1] .01027
• 2] .10127
• 3] 101.00027
• 4] 101.000027

Given, 168 × 32 = 5376 , then 5.376 ÷ 16.8 is equal to :

• 1] 0.032
• 2] 0.32
• 3] 3.2
• 4] 32

Which of the following is equal to 3.14 x 106 ?

• 1] 314
• 2] 3140
• 3] 3140000
• 4] None of these

Which of the following has fractions in ascending order?

• 1]

  2/3,3/5,7/9,9/11,8/9

• 2]

   

  3/5,2/3,9/11,7/9,8/9

• 3]

   

  3/5,2/3,7/9,9/11,8/9

• 4]

   

   8/9,9/11,7/9,2/3,3/5

\(\frac{{5 \times 1.6 - 2 \times 1.4}}{{1.3}} = ?\)

• 1] 0.4
• 2] 1.2
• 3] 1.4
• 4] 4

\(\frac{{0.0203 \times 2.92}}{{0.0073 \times 14.5 \times 0.7}} = ?\)

• 1] 0.8
• 2] 1.45
• 3] 2.40
• 4] 3.25

Evalute \(:\frac{{{{\left( {2.39} \right)}^2} - {{\left( {1.61} \right)}^2}}}{{2.39 - 1.61}}\)

• 1] 2
• 2] 4
• 3] 6
• 4] 8

The price of commodity X increases by 40 paise every year, while the price of commodity Y increases by 15 paise every year. If in 2001, the price of commodity X was Rs. 4.20 and that of Y was Rs. 6.30, in which year commodity X will cost 40 paise more than the commodity Y ?

• 1] 2010
• 2] 2011
• 3] 2012
• 4] 2013