The number of terms of the A.P. 3, 7, 11, 15, ....... to be taken so that the sum is 406 is
5
10
12
14
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1
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(1) + (1 + 1) + (1 + 1 + 1) + ....... + (1 + 1 + 1 + ...... n - 1 times) = ......
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2
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If the sum of the series 2 + 5 + 8 + 11 … is 60100, then the number of terms are
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3
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The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is
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4
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For an A.P. if a25 - a20 = 45, then d equals to:
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5
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If sum of n terms of an A.P. is 3n2 + 5n and Tm = 164 then m =
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6
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If 18, a, b - 3 are in A.P. then a + b =
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7
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The sum of first n odd natural numbers in
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8
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If the 3rd and the 5th term of an arithmetic progression are 13 and 21, what is the 13th term?
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9
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The 3rd and 8th term of an arithmetic progression are -13 and 2 respectively. What is the 14th term?
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10
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If k, 2k – 1 and 2k + 1 are three consecutive terms of an AP, the value of k is
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