# Quiz Discussion

The number of terms of the A.P. 3, 7, 11, 15, ....... to be taken so that the sum is 406 is

Course Name: Quantitative Aptitude

• 1]

5

• 2]

10

• 3]

12

• 4]

14

##### Solution
No Solution Present Yet

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# Quiz
1
Discuss

The sum of the first 16 terms of an AP whose first term and third term are 5 and 15 respectively is

• 1] 600
• 2] 765
• 3] 640
• 4] 680
• 5] 690
##### Solution
2
Discuss

For an A.P. if a25 - a20 = 45, then d equals to:

• 1] 9
• 2] -9
• 3] 18
• 4] 23
##### Solution
3
Discuss

If the first term of an A.P. is 2 and common difference is 4, then the sum of its 40 term is

• 1] 3200
• 2] 1600
• 3] 200
• 4] 2800
##### Solution
4
Discuss

The 7th and 21st terms of an AP are 6 and -22 respectively. Find the 26th term

• 1] -34
• 2] -32
• 3] -12
• 4] -10
• 5] -16
##### Solution
5
Discuss

What is the sum of the first 12 terms of an arithmetic progression if the first term is -19 and last term is 36?

• 1] 192
• 2] 230
• 3] 102
• 4] 214
##### Solution
6
Discuss

The 2nd and 6th term of an arithmetic progression are 8 and 20 respectively. What is the 20th term?

• 1]

56

• 2]

62

• 3]

65

• 4]

69

##### Solution
7
Discuss

Find the first term of an AP whose 8th and 12th terms are respectively 39 and 59.

• 1] 5
• 2] 6
• 3] 4
• 4] 3
• 5] 7
##### Solution
8
Discuss

What is the sum of the first 12 terms of an arithmetic progression if the first term is -19 and last term is 36?

• 1]

192

• 2]

230

• 3]

102

• 4]

204

##### Solution
9
Discuss

(1) + (1 + 1) + (1 + 1 + 1) + ....... + (1 + 1 + 1 + ...... n - 1 times) = ......

• 1]

$$\frac{{n\left( {n + 1} \right)}}{2}$$

• 2]

$$\frac{{n\left( {n - 1} \right)}}{2}$$

• 3]

$${n^2}$$

• 4]

n

##### Solution
10
Discuss

The common difference of the A.P. $$\frac{1}{3}, \frac{{1 - 3b}}{3} , \frac{{1 - 6b}}{3}$$   . . . . . . is

• 1]

$$\frac{1}{3}$$

• 2]

$$- \frac{1}{3}$$

• 3]

-b

• 4]

b

# Quiz