# Quiz Discussion

If the product of four consecutive natural numbers increased by a natural number p, is a perfect square, then the value of p is = ?

Course Name: Quantitative Aptitude

• 1] 1
• 2] 2
• 3] 4
• 4] 8
##### Solution
No Solution Present Yet

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# Quiz
1
Discuss

Solved $$\root 4 \of {{{\left( {625} \right)}^3}} = ?$$

• 1]

$$\root 3 \of {1875}$$

• 2]

25

• 3]

125

• 4]

None of these

##### Solution
2
Discuss

$$\left( {\frac{{\sqrt {625} }}{{11}} \times \frac{{14}}{{\sqrt {25} }} \times \frac{{11}}{{\sqrt {196} }}} \right){\kern 1pt}$$     is equal to :

• 1] 5
• 2] 6
• 3] 8
• 4] 11
##### Solution
3
Discuss

The number of digits in the square root of 625685746009 is = ?

• 1] 4
• 2] 5
• 3] 6
• 4] 7
##### Solution
4
Discuss

While solving a mathematical problem, Samidha squared a number and then subtracted 25 from it rather than the required i.e., first subtracting 25 from the number and then squaring it. But she got the right answer. What was the given number ?

• 1] 13
• 2] 38
• 3] 48
• 4] Cannot be determined
• 5] None of these
##### Solution
5
Discuss

Find the square root of 3 upto three decimal places

• 1]

1.732

• 2]

2.732

• 3]

1.222

• 4]

1.414

##### Solution
6
Discuss

Given $$\sqrt 2 = 1.414.$$   Then the value of $$\sqrt 8$$  + $$2\sqrt {32}$$  -  $$3\sqrt {128}$$  + $$4\sqrt {50}$$   is = ?

• 1] 8.426
• 2] 8.484
• 3] 8.526
• 4] 8.876
##### Solution
7
Discuss

The cube root of .000216 is:

• 1] .6
• 2] .06
• 3] 77
• 4] 87
##### Solution
8
Discuss

$$99 \times 21 - \root 3 \of ? = 1968$$

• 1] 1367631
• 2] 111
• 3] 1366731
• 4] 1367
##### Solution
9
Discuss

$${\left( {\sqrt 3 - \frac{1}{{\sqrt 3 }}} \right)^2}$$ simplifies to:

• 1]

3/4

• 2]

$$\frac{4}{{\sqrt 3 }}$$

• 3]

4/3

• 4]

None of these

##### Solution
10
Discuss

Given that $$\sqrt {13} = 3.605$$   and $$\sqrt {130} = 11.40$$  . find the value of $$\sqrt {1.30}$$  + $$\sqrt {1300}$$  + $$\sqrt {0.0130}$$   = ?

• 1] 36.164
• 2] 36.304
• 3] 37.164
• 4] 37.304
# Quiz