Quiz Discussion

Find the nth term of the following sequence :

Course Name: Quantitative Aptitude

  • 1]

    5(10n - 1)

  • 2]

    5n(10n - 1)

  • 3]

    \(\frac{5}{9} \times \left( {{{10}^n} - 1} \right)\)

  • 4]

    \({\left( {\frac{5}{9}} \right)^n} \times \left( {{{10}^n} - 1} \right)\)

Solution
No Solution Present Yet

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The 7th and 21st terms of an AP are 6 and -22 respectively. Find the 26th term

  • 1] -34
  • 2] -32
  • 3] -12
  • 4] -10
  • 5] -16
Solution
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What is the sum of all 3 digit numbers that leave a remainder of '2' when divided by 3?

  • 1]

    897

  • 2]

    1,64,850

  • 3]

    1,64,749

  • 4]

    1,49,700

Solution
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The 3rd and 7th term of an arithmetic progression are -9 and 11 respectively. What is the 15th term?

  • 1] 28
  • 2] 87
  • 3] 51
  • 4] 17
Solution
4
Discuss

The 3rd and 8th term of an arithmetic progression are -13 and 2 respectively. What is the 14th term?

  • 1] 23
  • 2] 17
  • 3] 20
  • 4] 26
Solution
5
Discuss

The two geometric means between the number 1 and 64 are

  • 1]

    8 and 16

  • 2]

    2 and 16

  • 3]

    4 and 8

  • 4]

    4 and 16

Solution
6
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If the sum of the series 2 + 5 + 8 + 11 … is 60100, then the number of terms are

  • 1]

    100

  • 2]

    150

  • 3]

    200

  • 4]

    250

Solution
7
Discuss

Find the 15th term of the sequence 20, 15, 10 . . . . .

  • 1] -45
  • 2] -55
  • 3] -50
  • 4] 0
Solution
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Discuss

If S1 is the sum of an arithmetic progression of ‘n’ odd number of terms and S2 is the sum of the terms of the series in odd places, then \(\frac{{{S_1}}}{{{S_2}}}\)

 

  • 1]

    \(\frac{{2n}}{{n + 1}}\)

  • 2]

    \(\frac{n}{{n + 1}}\)

  • 3]

    \(\frac{{n + 1}}{{2n}}\)

  • 4]

    \(\frac{{n - 1}}{n}\)

Solution
9
Discuss

Consider an infinite G.P. with first term a and common ratio r, its sum is 4 and the second term is 3/4, then

  • 1]

    a = 7/4, r = 3/7

  • 2]

    a = 2, r = 3/8

  • 3]

    a = 3, r = 1/4

  • 4]

    a = 3/2, r = ½

Solution
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If the sum of n terms of an A.P. be 3n2 + n and its common difference is 6, then its first term is

  • 1] 2
  • 2] 3
  • 3] 1
  • 4] 4
Solution
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